2x^2+7x-15=-3

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Solution for 2x^2+7x-15=-3 equation:



2x^2+7x-15=-3
We move all terms to the left:
2x^2+7x-15-(-3)=0
We add all the numbers together, and all the variables
2x^2+7x-12=0
a = 2; b = 7; c = -12;
Δ = b2-4ac
Δ = 72-4·2·(-12)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{145}}{2*2}=\frac{-7-\sqrt{145}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{145}}{2*2}=\frac{-7+\sqrt{145}}{4} $

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